If the area of the triangle $A B C$ is $96 s q . u n i t s$ , then $R r (sin A + sin B + sin C)$ is equal to

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Solution

$R r (sin A + sin B + sin C)$
$= R r (\frac{a}{2 R} + \frac{b}{2 R} + \frac{c}{2 R})$
$= R r (\frac{a + b + c}{2 R})$
$= R r \times \frac{2 s}{2 R}$
$= s r = △ = 96$

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