CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the areas of the adjacent faces of a rectangular block are in the ratio 2 : 3 : 4 and its volume is 9000 cm3, then the length of the shortest edge is


A

30 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

20 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

15 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

10 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

15 cm


Ratio in the areas of three adjacent faces of a cuboid = 2:3:4

Volume = 9000 cm3

Let the area of faces be 2x, 3x, 4x and

Let a, b, and c be the dimensions of the cuboid, then

2x=ab, 3x=bc, 4x=ca

ab×bc×ca=2x×3x×4x

a2b2c2=24x3

But volume = abc=9000 cm3

24x3=(9000)2

x3=8100000024=3375000

x=33375000=3(150)3=150

ab=300

bc=450

ca=600

abc=9000

Dividing one by one, we get

c=30, a=20, b=15

Shortest side = 15 cm


flag
Suggest Corrections
thumbs-up
46
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Volume of Solids
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon