Question

If the Arithmetic mean and Geometrical mean of three numbers are equal to x, then the each number is equal to

• A. x
• B. 2x
• C. $\sqrt{x}$
• D. $\sqrt[3]{3x}$

Answer 1

The correct option is A x

Given,

$x=\frac{a+b+c}{3}$ and $x=(abc{)}^{\frac{1}{3}}$

then,

$3x=a+b+c$ and $x^3=abc$

It is possible in only one case when each no is equal to x.

So each no. $=x$.