If the arithmetic mean of the distribution given below is 15, let use find the value of P.
Veriable 5 10 15 20 25
Frequency(f) 6 p 6 10 5

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Solution

$\frac{(5 \times 6) + (10 \times p) + (15 \times 6) + (20 \times 10) + (25 \times 5)}{(5 + 10 + 15 + 20 + 25)} = 15$
$\Rightarrow 30 + 10 p + 90 + 200 + 125 = 15 (75)$
$\Rightarrow 10 p + 445 = 1125$
$\Rightarrow 10 p = 680$
$p = 68$ .

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If the arithmetic mean of the distribution given below is 15, let use find the value of P.Veriable510152025Frequency(f)6p6105

(5×6)+(10×p)+(15×6)+(20×10)+(25×5)(5+10+15+20+25)=15⇒30+10p+90+200+125=15(75)⇒10p+445=1125⇒10p=680p=68.

If the arithmetic mean of the distribution given below is 15, let use find the value of P.
Veriable 5 10 15 20 25
Frequency(f) 6 p 6 10 5

$\frac{(5 \times 6) + (10 \times p) + (15 \times 6) + (20 \times 10) + (25 \times 5)}{(5 + 10 + 15 + 20 + 25)} = 15$
$\Rightarrow 30 + 10 p + 90 + 200 + 125 = 15 (75)$
$\Rightarrow 10 p + 445 = 1125$
$\Rightarrow 10 p = 680$
$p = 68$ .