If the arithmetic mean of the number x1,x2,x3.........,xn is ¯¯¯x , then the arithmetic mean of numbersax1,+b,ax2+b,ax3+b,.............axn+b,
where a, b are two constants would be
A
¯¯¯x
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B
na¯¯¯x+nb
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C
a¯¯¯x
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D
a¯¯¯x+b
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Solution
The correct option is Da¯¯¯x+b Requiredmean=(ax1+b)+(ax2+b)+....+(axn+b)n =a(x1+x2+....+xn)+nbn=¯¯¯¯¯¯ax+b, (∴x1+x2+...+xnn=¯¯¯x).