If the arithmetic mean of the observations x1,x2,x3,...,xn is 1, then the arithmetic mean of x1k,x2k,x3k,...,xnk(k>0) is :
A
greater than 1
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B
less than 1
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C
equal to 1
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D
none of these
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Solution
The correct option is D none of these We have, x1+x2+x3+...+xnn=1 ⇒x1+x2+x3+...+xn=n (Given) ∴ Required arithmetic mean =x1k+x2k+x3k+...+xnkn=1k(x1+x2+x3+...+xnn)=1k