The correct option is A √52 unit
Given equation of hyperbola is (x+y+1)2−(x−y−3)2=5
⇒ (2x−2)(2y+4)=5
⇒ (x−1)(y+2)=54
∴ Centre is (1,−2)
∵ Equation of asymptotes for the hyperbola (x−h)(y−k)=a2 are
x=h and y=k
∴ x=1 and y=−2 are the required asymptotes
Hence, we get A(1,−2), B(1,0) and C(0,−2)
So, △ABC will be rightangle triangle with A as rightangle
Hence radius of circum-circle of △ABC will be
r=BC2=√52 unit