If the atmosphere of the Earth is replaced with water, to what extent the water level must rise so as to maintain the same pressure $[10^{5} N m^{- 2}]$ on Earth's surface? [Assume nothing above the water surface. take $g = 10 m s^{- 2}$ , density of water $= 1000 k g m^{- 3}$ .

10 m

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5 m

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20 m

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15 m

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Solution

The correct option is A $10 m$
Given:
Pressure of Earth's atmosphere, $P_{o} = 10^{5} N m^{- 2}$ (approximately)
Let the height of water be $h$
Then, pressure due to water, $P = ρ h g$
[Neglecting variation in 'g' and constant density of water]
As per the given data,
$P = P_{o}$
$ρ h g = P_{o}$
$1000 \times 10 \times h = 10^{5}$
$\Rightarrow h = 10 m$

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If the atmosphere of the Earth is replaced with water, to what extent the water level must rise so as to maintain the same pressure [105 N m−2] on Earth's surface? [Assume nothing above the water surface. take g=10 m s−2, density of water =1000 kg m−3.

The correct option is A 10 mGiven: Pressure of Earth's atmosphere, Po=105 Nm−2 (approximately) Let the height of water be h Then, pressure due to water, P=ρhg [Neglecting variation in 'g' and constant density of water] As per the given data, P=Po ρhg=Po 1000×10×h=105 ⇒h=10 m

The maximum value of water pressure in the box in which water is filled upto a height of 4 m is equal to (atmospheric pressure =105 N/m2, density of water =1000 kg/m3, g=10 m/s2)

If the atmosphere of the Earth is replaced with water, to what extent the water level must rise so as to maintain the same pressure $[10^{5} N m^{- 2}]$ on Earth's surface? [Assume nothing above the water surface. take $g = 10 m s^{- 2}$ , density of water $= 1000 k g m^{- 3}$ .

The maximum value of water pressure in the box in which water is filled upto a height of $4 m$ is equal to (atmospheric pressure $= 10^{5} N / m^{2},$ density of water $= 1000 k g / m^{3}$ , $g = 10 m / s^{2}$ )