If the attraction force between two bodies separated by R is F, then find the force between them at distance (R+d).

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Solution

The correct option is A

Case - 1: According to Newton's law of gravitation

$F^{^{'}}$ = $\frac{G M_{1} M_{2}}{{(R + d)}^{2}}$

F = = $\frac{G M_{1} M_{2}}{R^{2}}$

Case - II :

$∴$ $\frac{F^{^{'}}}{F}$ = $\frac{R^{2}}{{(R + d)}^{2}}$ or $F^{^{'}}$ = $\frac{R^{2} F}{{(R + d)}^{2}}$

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If the attraction force between two bodies separated by R is F, then find the force between them at distance (R+d).

The correct option is A Case - 1: According to Newton's law of gravitation F′ = GM1M2(R+d)2 F = = GM1M2R2 Case - II : ∴ F′F = R2(R+d)2 or F′ = R2F(R+d)2

The correct option is A

Case - 1: According to Newton's law of gravitation

$F^{^{'}}$ = $\frac{G M_{1} M_{2}}{{(R + d)}^{2}}$

F = = $\frac{G M_{1} M_{2}}{R^{2}}$

Case - II :

$∴$ $\frac{F^{^{'}}}{F}$ = $\frac{R^{2}}{{(R + d)}^{2}}$ or $F^{^{'}}$ = $\frac{R^{2} F}{{(R + d)}^{2}}$