If the average of n natural numbers is (n+10)/4 then what is the value of n?

a.8 b.9 c.10 d.11

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Solution

Given that the mean of first n natural numbers = (n+10)/4.

We know that mean of n natural numbers = (n + 1)/2.

=> (n + 1)/ 2 = (n+10)/4

=> 2(n + 1) = n+10

=> 2n+2 = n+10

=> 2n-n = 10-2

=> n = 8

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