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Question

If the average of the following data is 20.2, find the value of p:
xf10615820P2510306

A
10
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B
16
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C
20
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D
14
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Solution

The correct option is C 20
(xi)fifixi1066015812020P20P2510250306180fi=30+Pfixi=610+20P
Given that Mean = 20.2
Mean=fixifi20.2=610+20P30+P

20.2 ( 30 + P ) = 610 + 20P
606 + 20.2P = 610 + 20P
20.2P – 20P = 610 – 606
0.2 P = 4
P = 20
The value of 'P' is 20.

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