Question

If the average velocity of $N_2$ molecules is $0.3m/sec$ at ${27}^{\circ }C$, then the velocity of $0.6m/sec$ will take place at :

• A. 273 K
• B. 927 K
• C. 1000 K
• D. 1200 K

Answer 1

Answer: (D)

1200 K

The average velocity is directly proportional to the square root of the temperature.

$\frac{v^{\prime }}{v}=\sqrt{\frac{T^{\prime }}{T}}$

$\frac{0.6}{0.3}=\sqrt{d\frac{T^{\prime }}{300}}$

$T^{\prime }=1200K$

So, the correct option is $D$