If the average velocity of the molecules of a gas is doubled, then what will happen to their most mean square velocity?

Doubled

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Halved

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Becomes

\sqrt{2}

times

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Becomes

\frac{1}{\sqrt{2}}

times

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Solution

The correct option is A Doubled
Average velocity of gas molecules is given by $V_{a v e r a g e} = \sqrt{\frac{8 R T}{π M}}$

Most probable velocity is given by $V_{m o s t - p r o b a b l e} = \sqrt{\frac{2 R T}{M}}$
As both the average velocity and most probable velocity depends on same parameters, if we double average velocity the most mean square velocity also gets doubled.
Hence,option A is correct answer.

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