As we already know,
Hypotenuse = √P2+B2, where P and B are the lengths of perpendicular and base respectively. ...(0.5 marks)
So, in order to solve it, we have to first round off the base and perpendicular to its tens place:
Rounding off 33 we get 30 ...(0.5 marks)
( Ones place is 3, less than 5)
Similarly, rounding off 42 you get 40 ...(0.5 marks)
( Ones place is 2, less than 5)
Now, we can find the approximate value of the hypotenuse
Hypotenuse = √P2+B2
=√302+402 ...(0.5 marks)
= √2500 = 50m ...(0.5 marks)
Thus, the answer is 50 m ...(0.5 marks)