If the base BC = 6 cm and the altitude AP = 4 cm, then the area of the triangle ABC = .

12 c m^{2}

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15 c m^{2}

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24 c m^{2}

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Solution

The correct option is A $12 c m^{2}$
Given,
Base BC = 6 cm
Altitude AP = 4 cm

$∵ Area of a triangle = \frac{1}{2} \times b a s e \times h e i g h t$
$\Rightarrow Area = \frac{1}{2} \times 6 \times 4 = 12 c m^{2}$

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If the base BC = 6 cm and the altitude AP = 4 cm, then the area of the triangle ABC = .

The correct option is A 12 cm2Given, Base BC = 6 cm Altitude AP = 4 cm ∵Area of a triangle=12×base×height ⇒Area = 12× 6× 4 = 12 cm2

The correct option is A $12 c m^{2}$
Given,
Base BC = 6 cm
Altitude AP = 4 cm

$∵ Area of a triangle = \frac{1}{2} \times b a s e \times h e i g h t$
$\Rightarrow Area = \frac{1}{2} \times 6 \times 4 = 12 c m^{2}$