Question

If the base of a parallelogram is $(x+4)$, altitude to the base is $(x-3)$ and the area is $(x^2-4)$, then what is the actual area equal to?

• A. $60$ sq units
• B. $45$ sq units
• C. $77$ sq units
• D. $96$ sq units

Answer 1

Answer: (A)

$60$ sq units

Area of the parallelogram $=$ base $\times$ altitude
$\Rightarrow (x+4)\times (x-3)=x^2+4x-3x-12$
$=x^2+x-12$
Given, $x^2+x-12=x^2-4$

$\Rightarrow x=8$
$\therefore$Actual area $={\left(8\right)}^2-4=64-4=60$ sq units