If the base of a triangular field is 12cm and height is 14cm.What will be the area of the triangle in ${c m}^{2}$ ?

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Solution

Area of a triangle= $\frac{1}{2} \times b a s e \times h e i g h t$

$\Rightarrow$ Area of a triangle= $\frac{1}{2} \times 12 \times 14 = 84 {c m}^{2}$ .

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