If the binding energy of deuterium is 2.23 MeV, then the mass defect (in amu) is?
0.0012 MeV
0.0036 MeV
0.0024 MeV
0.0048 MeV
Binding energy E=Δm×931MeV
Given, the binding energy of Deuterium = 2.23 MeV
⇒ Δm = E931 MeV =2.23931 =0.0024 amu