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Question

If the binding energy of deuterium is 2.23 MeV, then the mass defect (in amu) is?


A

0.0012 MeV

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B

0.0036 MeV

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C

0.0024 MeV

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D

0.0048 MeV

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Solution

The correct option is C

0.0024 MeV


Binding energy E=Δm×931MeV

Given, the binding energy of Deuterium = 2.23 MeV

Δm = E931 MeV =2.23931 =0.0024 amu


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