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Internal Energy

If the bindin...

Question

If the binding energy per nucleon in Li⁷ and He⁴ nuclei are 5.60 MeV and 7.06 MeV , then what is the energy of the reaction ₃Li⁷ + ₁H¹ = 2 ₂He⁴ ?

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Solution

Applying principle of energy conservation, Energy of proton
= total B.E. of 2a - energy of Li7
= 8 × 7.06 - 7 × 5.6
= 56.48 - 39.2 = 17.28 MeV

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