Question

If the bisector of an angle of a triangle bisects the opposite side then the triangle is isosceles.
If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

Consider $△ABC$, such that BD bisect $\angle BAC$ and biscets the side BC
Now,in $triangle$s, ABD and ACD,
$\angle BAD=\angle CAD$ (AD bisects $\angle BAC$)
$BD=CD$ (AD bisects side BC)
$AD=AD$ (Common)
Thus, $△ABD\cong △ACD$ (SAS rule)
Hence, AB = AC (By CPCT)
Or $△ABC$ is an Isosceles triangle.