If the bisector of an angle of a triangle bisects the opposite side then the triangle is isosceles. If the above statement is true then mention answer as 1, else mention 0 if false
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Solution
Consider △ABC, such that BD bisect ∠BAC and biscets the side BC Now,in triangles, ABD and ACD, ∠BAD=∠CAD (AD bisects ∠BAC) BD=CD (AD bisects side BC) AD=AD (Common) Thus, △ABD≅△ACD (SAS rule) Hence, AB = AC (By CPCT) Or △ABC is an Isosceles triangle.