If the bisector of the exterior vertical angle of a triangle be parallel to the base. Show that the triangle is isosceles.
Given : In ΔABC, AE is the bisector of vertical exterior ∠A and AE || BC
To prove : ΔABC Is an isosceles
Proof : ∵ AE || BC
∴ ∠1=∠B (Corresponding angles)∠2=∠C (Alternate angle)But ∠1=∠2(∵ AE is the bisector of ∠CAD)∴ ∠B=∠C∴ AB=AC (Sides opposite to equal angles)∴ ΔABC is an isosceles triangle