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Question
If the bisector of the lines x2−2pxy−y2=0 be x2−2qxy−y2=0, then
If the bisector of the lines x2−2pxy−y2=0 be x2−2qxy−y2=0, then
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Solution
The correct option is A
Bisector of the angle between the lines x2−2pxy−y2=0 is x2−y2xy=1−(−1)−p
⇒px2+2xy−py2=0
But it is represented by x2−2qxy−y2=0.
Therefore p1=2−2q⇒pq=−1.
Bisector of the angle between the lines x2−2pxy−y2=0 is x2−y2xy=1−(−1)−p
⇒px2+2xy−py2=0
But it is represented by x2−2qxy−y2=0.
Therefore p1=2−2q⇒pq=−1.