If the bisectors of a pair of corresponding angles formed by transversal are parallel, then prove that given lines are parallel.
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Solution
Given: AB and CD are two straight lines cut by a transversal EF at G and H respectively. GM and HN are the bisectors of corresponding angles ∠EGB and ∠GHD respectively such that GM∥HN. To Prove: AB∥CD Proof: ∵GM∥HN ∴∠1=∠2 (Corresponding angles) ⇒2∠1=2∠2⇒∠EGB=∠GHD⇒AB∥CD (∠EGB & ∠GHD are corresponding angles formed by transversal EF with AB and CD and are equal.) Hence, proved.