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Question

If the bisectors of angles ABC and ACB of a triangle ABC meet at a point O, then prove that BOC=90o+12A.

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Solution

Given :
A ABC such that the bisectors of ABC and ACB meet at a point O.
To prove :
BOC=90o+12A

Proof :
In BOC,
1+2+BOC=180o
In ABC,
A+B+C=180o
A+2(1)+2(2)=180o
A2+1+2=90o

1+2=90oA2

Therefore,
90oA2+BOC=180o

BOC=90o+A2

1334043_1111833_ans_edef39458a7f41ea867cc052d4006a13.png

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