If the bond energies of H–H, Br–Br, and H–Br are 433,192 and 364kJ mol–1 respectively, the ΔHo for the reaction H2(g)+Br2(g)→2HBr(g) is:
A
–261kJ
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B
+103kJ
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C
+261kJ
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D
–103kJ
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Solution
The correct option is D–103kJ We know that, H2+Br2→2HBr H−H433+Br−Br192→2H−Br2×364=728
Net energy released =728–433−192=103kJ
Since, energy is released, ΔHo=−103kJ.