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Hydrogenation of Alkynes

If the bond e...

Question

If the bond energies of H – H, Br – Br and H – Br are 433, 192 and 364 kJ $m o l^{- 1}$ respectively, the $Δ H^{\circ}$ for the reaction ; $H_{2} (g) + B r_{2} (g) \to 2 H B r (g)$ is

A

– 261 kJ

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B

+ 103 kJ

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C

+ 261 kJ

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D

– 103 kJ

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Solution

The correct option is D – 103 kJ
$Δ H^{\circ} = \sum B . E (r e a c t a n t s) - \sum B . E (p r o d u c t s) = [B . E (H - H) + B . E (B r - B r)] - [2 B . E (H - B r)] = (433 + 192) - (2 \times 364) = 625 - 728 = - 103 k J$

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