If the Boolean expression (p⊕q)∧(∼p⊙q) is equivalent to p∧q, where ⊕,⊙∈{∧,∨}, then the ordered pair (⊕,⊙) is:
A
(∧,∧)
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B
(∧,∨)
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C
(∨,∨)
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D
(∨,∧)
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Solution
The correct option is B(∧,∨) pq∼pp∨qp∧q∼p∨q∼p∧qTTFTTTFTFFTFFFFTTTFTTFFTFFTF (p∨q)∧(∼p∨q)(p∨q)∧(∼p∧q)(p∧q)∧(∼p∨q)(p∧q)∧(∼p∧q)TFTFFFFFTTFFFFFF From the truth table, we observe that (p⊕q)∧(∼p⊙q)=p∧q