If the Boolean expression (p⇒q)⇔(q*(~P))is a tautology, then the Boolean expression p*(~q) is equivalent to:
p⇒~q
p⇒q
q⇒p
~q⇒p
Explanation for the correct option.
The table for boolean expression (p⇒q)⇔(q*(~P)) is:
~(~q∧p)=q∨~p=~p∨q*isequivalentto∨=~q∨p=q⇒p
Hence, option C is correct.