Question

If the breaking force for a given wire is $F$, then the breaking force of two wires of same magnitude will be

• A. $F$
• B. $2F$
• C. $4F$
• D. $8F$

Answer 1

The correct option is C $4F$

$Force=stress\times area$
$F=S\times \pi r^2$
So, $F\alpha r^2$
$\frac{F.}{F_1}=\frac{r^2}{(2r{)}^2}=\frac{1}{4}$
So, $F_1=4F$