If the capillary rise of water in a 1 mm diameter tube is 3 cm, the height of capillary rise of water in a 0.2 mm diameter tube in cm will be -
Capillary rise in a capillary tube, h=4Tcosθρgd
Where T= Surface tension
θ=Contact angle
ρ=Density of liquid
d= Diameter of the capillary tube
Hence, h∝1d
h1h2 = d2d1
Data given:d1=1 mm,h1=3 cm, d2=0.2 mm
hence h2=h1d1d2=3×10.2 cm =15 cm