Question

If the cartesian product A $\times$ A has 16 elements among which a few elements are found to be (-1, 0), (0, 1), (1, 2), then find set A.

• A. {-1, 0, 2, 3}
• B. {-1, 0, 1}
• C. {-1, 0, 1, 2}
• D. {0, 1, 2, 3}

Answer 1

The correct option is C

{-1, 0, 1, 2}

Since A $\times$ A has 16 elements
So, A should have 4 elements
Four distinct elements in A is {-1, 0, 1, 2}
Therefore, set A = {-1, 0, 1, 2}