Question

If the Cartesian product A $\times$ A has 32 elements among which few elements are found to be (-2, -1), (0, -1), (1, 0), (-2, 2). Find set A.

• A. {-1, 0, 2, 3}
• B. {-1, 0, 1}
• C. {-1, 0, 1, 2}
• D. {0, 1, 2, 3}

Answer 1

The correct option is C

{-1, 0, 1, 2}

Since A $\times$ A has 32 elements

So, A should have 5 elements. Only if A has elements { -2,-1, 0, 1, 2} then A X A can result some elements as (-2, -1), (0, -1), (1, 0), (-2, 2).

So, five distinct elements in A $\times$ A = {-2,-1, 0, 1, 2}

Therefore, set A = {-2,-1, 0, 1, 2}