If the centre of a regular hexagon is at origin and one of the vertices on Argand plane is at 1+2i and its perimeter is k units, then the numerical value of k2 is
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Solution
∠A2OA3=60∘,OA2=OA3, so △OA2A3 is equilateral Now, A2A3=OA3⇒A2A3=|1+2i|=√5