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Question

If the centroid of an equilateral triangle is (1, 1) and its one vertex is (-1, 2), then the equation of its circumcircle is


A

x2+y22x2y3=0

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B

x2+y2+2x2y3=0

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C

x2+y2+2x+2y3=0

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D

none of these

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Solution

The correct option is A

x2+y22x2y3=0


x2+y22x2y3=0
Fig.

The centre of the circumcircle is (1, 1).

Radius of the circumcircle

=(1+1)2+(12)2=5

Equation of the circle :

(x1)2+(y2)2=5

x2+y22x2y3=0


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