If the chords of contact of tangents from two points (−4,2) and (2,1) to the hyperbola x2a2−y2b2=1 are at right angle, then the ecentricity of the hyperbola is
A
√72
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B
√53
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C
√32
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D
√2
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Solution
The correct option is C√32 The chord of contact from (x1y1) to hyperbola x2a2−y2b2=1 is given by xx1a2−yy2b2=1