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Question

If the chords of the rectangular hyperbola x2y2=a2 touch the parabola y2=4ax, then the locus of their mid-points is:

A
x2(ya)=y3
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B
y2(xa)=x3
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C
x(y2a)=y
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D
y(x2a)=x
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Solution

The correct option is C y2(xa)=x3
Let P(h,k) be the midpoint of the chord,
Thus equation of chord to the hyperbola x2y2=a2 is,
hxky=h2k2y=hkx+kh2k
Now given this line touches parabola y2=4ax, so using condition of tangency,
c=amkh2k=akh
k2(ha)=h3
Therefore, locus of P(h,k) is, y2(xa)=x3
Hence, option 'B' is correct.

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