The correct option is A (2,3)
s2:x2+y2=6x−8t+10=0 centre =(3,4)
So, radial axis of s and s1 passes through (0,0)
So, radical axis of s and s2 passes through (Q,1).
So, radical axis of s and s3 pass through (−1,2)
from (1) & (2)
f=−3 and g=−2
So, centre of circle is (−g,−f)=(2,3)