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Byju's Answer
Standard XII
Mathematics
Orthogonality of Two Circles
If the circle...
Question
If the circle
x
2
+
y
2
+
2
x
+
2
k
y
+
6
=
0
and
x
2
+
y
2
+
2
k
y
+
k
=
0
intersect orthogonality, then
k
is:
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Solution
We have,
x
2
+
y
2
+
2
x
+
2
k
y
+
6
=
0
x
2
+
y
2
+
2
k
y
+
k
=
0
2
×
1
×
0
+
2
×
k
×
k
=
6
+
k
2
k
2
=
k
+
6
2
k
2
=
k
+
6
2
k
2
−
k
−
6
=
0
2
k
2
−
4
k
+
3
k
−
6
=
0
(
2
k
+
3
)
(
k
−
2
)
=
0
k
=
−
3
2
k
=
2
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0
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If the circle
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y
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Standard XII Mathematics
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