If the circle x2+y2+52Kx+2y+K=0 and 2(x2+y2)+2Kx+3y−1=0,(K∈R), intersect at the points P and Q. then the line 4x+5y−K=0 passes through P and Q for:
A
exactly two values of K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
exactly one value of K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
no value of K
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
infinitely may values of K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B no value of K Equation of common chord 4kx+12y+k+12=0 ...(1) and given line is 4x+5y−k=0 ...(2) On comparing (1) & (2), we get k=110=k+12−k