CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

If the circle x2+y2=9 touches the circle x2+y2+6y+c=0, then c is equal to-

A
27
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
36
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
36
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
27
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 27
x2+y2=9
centre (c1)=(0,0)
radius (r1)=3
x2+y2+6y+c=0
centre (c2)=(0,3)
radius (r2)=g2+f2c
=0+9c
=9c
since the circle intersect each other
So, c1c2=r1+r2
3=3+9c
9c=0
c=9
or c1c2=r1r2
3=39c
9c=0
c=9
or c1c2=r2r1
3=9c3
9c=6
9c=36
c=27
Therefore c=27

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Two Circles Touching Internally and Externally
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon