CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the circle x2+y2=a2 intersects the hyperbola xy=c2 at four points
P(x1,y1),Q(x2,y2),R(x3,y3), and S(x4,y4), then

A
x1+x2+x3+x4=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
y1+y2+y3+y4=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x1x2x3x4=c4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
y1y2y3y4=c4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D y1y2y3y4=c4
Putting y=c2x in x2+y2=a2, we get
x2+c4x2=a2or x4a2x2+c4=0As x1,x2,x3, and x4 are the roots of (i), we have
x1+x2+x3+x4=0 and x1x2x3x4=c4
Similarly, forming equation in y, we get
y1+y2+y3+y4=0 and y1y2y3y4=c4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon