If the circumference of a circle is 'C' and its radius is 'r', then which of the following relations is true for any circle?

C > 6r

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C < 6r

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C > 7r

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C > 8r

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Solution

The correct option is A C > 6r
Circumference(C) of a circle of radius r
= 2 $π$ r
We also know that $π$ = 3.141
So, C = 2 $π$ r = 2 x 3.141 x r
⇒ C = 6.282r
We know that , 6.28 > 6
Multiplying both sides with r(r>0).
We get, 6.28r > 6r
Hence, C = 6.28r > 6r

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If the circumference of a circle is 'C' and its radius is 'r', then which of the following relations is true for any circle?

The correct option is A C > 6rCircumference(C) of a circle of radius r = 2 π r We also know that π = 3.141 So, C = 2 π r = 2 x 3.141 x r ⇒ C = 6.282r We know that , 6.28 > 6 Multiplying both sides with r(r>0). We get, 6.28r > 6r Hence, C = 6.28r > 6r

The correct option is A C > 6r
Circumference(C) of a circle of radius r
= 2 $π$ r
We also know that $π$ = 3.141
So, C = 2 $π$ r = 2 x 3.141 x r
⇒ C = 6.282r
We know that , 6.28 > 6
Multiplying both sides with r(r>0).
We get, 6.28r > 6r
Hence, C = 6.28r > 6r