Question

If the circumference of the inner edge of a hemispherical bowl is $\frac{132}{7}cm$, then what is its capacity?

• A. $12\pi c{m}^3$
• B. $18\pi c{m}^3$
• C. $24\pi c{m}^3$
• D. $36\pi c{m}^3$

Answer 1

Answer: (B)

$18\pi c{m}^3$

$2\pi r=\frac{132}{7}\Rightarrow r=\frac{132}{7}\times \frac{1}{2\times \frac{22}{7}}$
$r=3$
$Capacity=\frac{2}{3}.\pi r^3=\frac{2}{3}.\pi 3^3=18\pi$