If the class intervals are $10 - 19, 20 - 29, 30 - 39, . . .$ then the upper limit of the first class-interval is

19.5

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19

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20

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None of these

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Solution

The correct option is A $19.5$
$10 - 19, 20 - 29, 30 - 39, . . .$
Here the class intervals are not continuous. To make them continuous take the mean of upper limit of first class and lower limit of second class.
Mean $= \frac{19 + 20}{2} = 19.5$ , which gives the upper limit of first class and lower limit of second class for the continuous class intervals.

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If the class intervals are 10−19,20−29,30−39,... then the upper limit of the first class-interval is

If the class intervals are $10 - 19, 20 - 29, 30 - 39, . . .$ then the upper limit of the first class-interval is