If the classes in a grouped frequency distribution are not continuous, we can make them continuous by finding half of the difference between the upper limit of a class and the lower limit of the next class, and then adding the same to all the lower limits and subtracting it from all the upper limits in the distribution.

True

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False

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Solution

The correct option is B False
We find the difference between the upper limit of a class and the lower limit of its succeeding class. We then add half of this difference to each of the upper limits and subtract the same from each of the lower limits.

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If the classes in a grouped frequency distribution are not continuous, we can make them continuous by finding half of the difference between the upper limit of a class and the lower limit of the next class, and then adding the same to all the lower limits and subtracting it from all the upper limits in the distribution.

State true or false.
If the classes in a grouped frequency distribution are not continuous, we can make them continuous by finding half of the difference between the upper limit of a class and the lower limit of the next class, and then adding the same to all the lower limits and subtracting it from all the upper limits in the distribution.

Q. For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abscissae are respectively
(a) upper limits of the classes
(b) lower limits of the classes
(c) class marks of the classes
(d) upper limits of preceding classes

Q. Let

m

be the mid-point and

l

the upper class limit of a class in a continuous frequency distribution. The lower limit of the class is

Q. Let

m

be the class-mark and

u

be the upper limit of a class in a continuous frequency distribution. The lower limit of the class is _________.

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The correct option is B FalseWe find the difference between the upper limit of a class and the lower limit of its succeeding class. We then add half of this difference to each of the upper limits and subtract the same from each of the lower limits.

The correct option is B False
We find the difference between the upper limit of a class and the lower limit of its succeeding class. We then add half of this difference to each of the upper limits and subtract the same from each of the lower limits.