If the co-ordinates of the points P and Q be (1, –2, 1) and (2, 3, 4) and O be the origin, then
OP = OQ
OP 丄 OQ
OP || OQ
None of these
Let's find a1a2+b1b2+c1c2 (1).(2)+(−2)(3)+(1)(4) = 0 Since, a1a2+b1b2+c1c2 = 0 Therefore OP 丄 OQ.
If the co-ordinates of the points P,Q,R,S be (1, 2, 3), (4, 5, 7), (– 4, 3, – 6) and (2, 0, 2) respectively, then
The co-ordinates of two points P and Q are (x1,y1) and (x2,y2) and O is the origin. If circles be described on OP and OQ as diameters then length of their common chord is