If the coefficient of 4th and 13th terms in the expansion of x2 - 1xn be equal then find the term which is independent of x-

^nC_3 = ^nC_12 ⇒ n = 15 #160; ( x^2 + 1x )^15. #160; We have to find the term independent of x . It will be 11th term #160; T_1 ...

137

You visited us 137 times! Enjoying our articles? Unlock Full Access!

Term Independent of x

If the coeffi...

Question

If the coefficient of 4th and 13th terms in the expansion of ${(x^{2} + \frac{1}{x})}^{n}$ be equal then find the term which is independent of x.

Open in App

Solution

Suggest Corrections

Similar questions

If the coefficients of 7^th and 13^th terms in the expansion of (1 + x)ⁿ are equal, then n is equal to

7^{t h}

13^{t h}

(1 + x)^{n}

n =

{(x + y)}^{n}

4 t h

13 t h

^{'} n^{'}

The $13^{t h}$ term in the expansion of ${(x^{2} + \frac{2}{x})}^{n}$ is independent of x, then the sum of divisors of n is

{(x^{2} + \frac{2}{x})}^{n}

13^{t h}

Join BYJU'S Learning Program