If the coefficient of friction between A and B is μ, the maximum acceleration of the wedge A for which B remains at rest with respect to the wedge is
A
μg
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B
g(1+μ1−μ)
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C
g(1−μ1+μ)
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D
gμ
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Solution
The correct option is Bg(1+μ1−μ) The FBD of B is Here the block B experiences pseudo force towards left in the A frame. By balancing the equation perpendicular to the incline we get,
N=masinθ+mgcosθ
Now balancing the forces along the incline plane, macosθ=mgsinθ+f In limiting case, (f=μN) Hence we get, masinθ=mgsinθ+μ(masinθ+mgcosθ)
By putting θ=45o we get, a×1√2=g×1√2+μ(a×1√2+g×1√2)