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Question

If the coefficient of x1274 in the expansion of (x+1)(x2)2(x+3)3(x4)4(x+49)49(x50)50 is k, then the value of k is

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Solution

Degree of expansion is
1+2+3++50=50×512=1275
Coefficient of x1274=1 2C1(2)+ 3C2(3) 4C3(4)+=1222+3242++492502=3799=(3+7++99)
It is a A.P.
a=3, d=499=3+4(n1)n=25

Therefore, the required coefficient
=252[3+99]=25×51=1275k=1275

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