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Question

If the coefficient of x7 in [ax+(1bx)]11is 55a11, then a and b satisfy the relation

A
a+b=1
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B
ab=1
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C
ab=1
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D
ab=1
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Solution

The correct option is C ab=1
General term of [ax+(1bx)]11 is,
Tr+1=11Cr(ax)r(1bx)11r=11Crarbr11x2r11
Let Tr+1 posses x72r11=7=>r=9
Hence coefficient of x7 is =11C9a9b2=55a9b2=55a11 (given)
a2b2=1ab=±1

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